# the speed necessary to go into orbit around the earth is 8km/h.it is also necessary to travel about 200 km in order to get out of the atmosphere suppose a rocket can reach their speed after travelling 200 km under constant acceleration what could be the acceleration

### Asked by priyabanswar9140 | 15th Oct, 2020, 11:30: AM

Expert Answer:

### Let us assume the rocket has to travel a distance 200 km with constant acceleration
to reach final speed 8 km/hr [ 8 × (5/ 18) = 2.22 m/s]
Constant acceleration a is detrmined using following equation of motion , " v^{2} = u^{2} + ( 2 a S ) "
where v = 2.22 m/s is final speed , u is initial speed that is zero because rocket starts from rest
and S = 200 km is the distance travelled
2.22 × 2.22 = 2 × a × 200 × 10^{3}
we get constant acceleration a = 1.235 × 10^{-5} m/s^{2}

^{2}= u

^{2}+ ( 2 a S ) "

^{3}

^{-5}m/s

^{2}

### Answered by Thiyagarajan K | 17th Oct, 2020, 12:55: PM

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